Question

ABCD IS AN isosceles trapezium with AB parallel to CD and AD = BC.ANGLE A = 60, CD = 20cm and BC = 10 cm. Find AB. ​

Answer 1

Answer:

Answer is 10

Step-by-step explanation:

10, is the answer to your question

Answer 2

Answer:  

The value of AB is 10 cm.

Solution:

Given Data:  

According to the question:

To Find:

Find AB.  

Step 1:

AD=BC=10 cm

Angle A=60

Step 2:

CD=20 cm

In, ABC

OA divides BC into half

Therefore OB=OC=5CM

Step 3:

With respect to AOB angle A=30

Therefore from OAB,

Sin 30= OB/AB

The value of sin 30 $\frac{1}{2}$

0.5 =$\frac{5}{A B}$

Step 4:

0.5 AB =5

Step 5:

AB =$\frac{5}{0.5}$

AB=10 cm

Step 6:

Result:

Therefore the value of AB is 10 cm.