Question

ABCD is an isosscles trapezium. AB and DC are the parallel sides. perpendiculars DE and CF are drawn on AB. find out if ∆AD ~= ∆BCF
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Answer 1

Answer:

In △ADE and △BCF

In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)

In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)∠CFB=∠DEA=90

In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)∠CFB=∠DEA=90 AD=BC

In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)∠CFB=∠DEA=90 AD=BC △ADE≈△BCF (by ASA)

Step-by-step explanation:

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