Question

ABCD is an isosscles trapezium. AB and DC are the parallel sides. perpendiculars DE and CF are drawn on AB. find out if ∆AD ~= ∆BCF
​

Answer 1

Answer:

can you send the pic of this question

Answer 2

Answer:

In △ADE and △BCF

• In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)
• In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)∠CFB=∠DEA=90
• In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)∠CFB=∠DEA=90 AD=BC

In △ADE and △BCF∠A=∠B (Base angle is same in isosceles)∠CFB=∠DEA=90 AD=BC △ADE≈△BCF (by ASA)