Question

ABCD is an rectangle find the value of x and y a b is equal to 22 BC is equal to 16 CD is equal to X + Y AD is equal to X - y

Answer 1

Answer:

Step-by-step explanation:

CD = AB = X+Y = 22 (As ABCD is a rectangle, AB = CD) - I

AD = BC = X-Y = 16 (As ABCD is a rectangle, AD = BC) - II

Add I and II, you get

-> X+Y + (X-Y) = 2*X = 22+16 = 38

=> 2*X = 38

=> X = (38/2) = 19

Subtract II from I, you get

-> X+Y - (X-Y) = 2*Y = 22-16 = 6

=> 2*Y = 6

=> Y = (6/2) = 3

So, X=19 and Y=3