ABCD is asquare of side 1 cm O is the point of intersection of the diagonals. P is the mid-point of OB.Then the length of AP square in cm is
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by the Pythagorean theorem
AC=√2
Op=1/√2
=(√2)^2+(1/√2)^2
=2+1/2
=5/2
=2.5cm
AC=√2
Op=1/√2
=(√2)^2+(1/√2)^2
=2+1/2
=5/2
=2.5cm
Answered by
4
Answer:
Step-by-step explanation:
Diagonal length of square is √2
O is the point of intersection of diagonals.
OA,OB is half the diagonal lengthi.e1/√2
P is the midpoint of OB.
OP is1/2√2
From the triangleAOP
Using pythogras theorem
AP^2 = OP^2+OA^2
AP^2 =(1/2√2)^2+(1/√2)^2
AP^2 = 1/8+1/2 =5/8
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