ABCD is cyclic quadrilateral in which AB ll CD.If angle B=65°,find the other angles.
Answers
Answer:
∠B + ∠D = 180° (Opposite angles of cyclic quadrilateral) ⇒ ∠65° + ∠D = 180° ⇒ ∠D = 180° – 65° = 115° Since AB || CD and BC is the transversel ∴ ∠B + ∠C = 180° ⇒ 65° + ∠C = 180° ⇒ ∠C = 180° – 65° ⇒ ∠C = 115° Now, ∠A + 115° = 180° (Opposite angles of cyclic quadrilateral) ⇒ ∠A = 180° – 115° ⇒ ∠A = 65°
Answer:
angle a is 115 angle c is 65 angle d is 115