Math, asked by ShivKumarChauhan, 10 months ago

ABCD is cyclic quadrilateral whose diagonal intersect at point E angle DBC= 70° angle BAC= 30° find angle BCD​

Answers

Answered by vaibhavimurumkar2003
19

Answer:

qudrlateral ABCD is cyclic

opposite angel of cyclic quadrilateral are supplementary

therefore

angle BAC+angle BCD =180

angle BCD=180-30

HENCE

ANGLE BCD=150

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