abcd is cyclic quadrilatral find its angles
a =5x+5
B=7X+25
C=7Y+30
D=5Y
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The sum of two opposite angles in a cyclic quadrilateral is equal to 180 degrees (supplementary angles).
Angle A + Angle C = 180°
5x+5+7y+30=180
5x +7y =145 -(eq1)
Angle B + Angle D = 180°
7x +25+5y =180
7x+5y = 155 -(eq2)
On solving eq1 and eq 2
x=15
y=10
Angle A = 5(15) +5 =80°
Angle B = 7(15) +25 =130°
Angle C =7(10) +30 = 100°
Angle D = 5(10) =50°
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