ABCD is ||gm with side AB= 12cm. it's diagonals AC and BC are of lengths 20 cm and 16 cm respectively. find the area of ||gm ABCD
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Answer:
Area of Parallelogram ABCD=2×ar△ABC
ar△ABC=s(s−a)(s−b)(s−c)
s=2a+b+c=216+10+12=19cm
ar△ABC=19(19−16)×(19−10)(19−12)
=169×3×9×7
=59.9cm2
∴ area of parallelogram ABCD=2×59.9=119.8cm2
Now, area of parallelogram ABCD=base X height
119.8=10×h⇒h=11.98cm
∴ Distance between the shortest sides is 11.98cm
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