ABCD is parallelogram, if zB = 80°, then (<A + 2C) is:
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Answered by
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Given ABCD is a parallelogram.
The co-interior angles are always 180°
Given ∠B=100°
i.e, ∠B+∠C=180°
⇒∠C=80°
The opposite angles of a parallelogram are equal
i.e, ∠A=∠C=80°
⇒∠B=∠D=100°
∴ Sum of ∠A+∠C=80°+80°=160°
Hence, the answer is 160°.
Answered by
0
Answer:
Given ABCD is a parallelogram.
The co-interior angles are always 180°
Given ∠B=100°
i.e, ∠B+∠C=180°
⇒∠C=80°
The opposite angles of a parallelogram are equal
i.e, ∠A=∠C=80°
⇒∠B=∠D=100°
∴ Sum of ∠A+∠C=80°+80°=160°
Hence, the answer is 160°.
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