Math, asked by aarthibaldava9959722, 3 months ago

ABCD is parallelogram, if zB = 80°, then (<A + 2C) is:​

Answers

Answered by Anonymous
5

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Given ABCD is a parallelogram.

The co-interior angles are always 180°

Given ∠B=100°

i.e, ∠B+∠C=180°

⇒∠C=80°

The opposite angles of a parallelogram are equal

i.e, ∠A=∠C=80°

⇒∠B=∠D=100°

∴ Sum of ∠A+∠C=80°+80°=160°

Hence, the answer is 160°.

Answered by Anonymous
0

Answer:

Given ABCD is a parallelogram.

The co-interior angles are always 180°

Given ∠B=100°

i.e, ∠B+∠C=180°

⇒∠C=80°

The opposite angles of a parallelogram are equal

i.e, ∠A=∠C=80°

⇒∠B=∠D=100°

∴ Sum of ∠A+∠C=80°+80°=160°

Hence, the answer is 160°.

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