Math, asked by sangitasingh2511, 7 hours ago

ABCD is parallelogram with A = 80°. The internal bisectors of B and C meet each other at O. Find the

measure of the three angles of BCO​

Answers

Answered by DIVYGAURAV
2

Answer:

B =50

C =40

D =90

Step-by-step explanation:

A = 80

C=80 ( opp. angle of parallelogram)

B = 100 (co.interior angle sum)

D=100(opp. angle of parallelogram)

In triangle BCO

angle B=50. (100\2)

angle C =40. (80\2)

angle O =90. (180-50-40)

Similar questions