ABCD is parallelogram with A = 80°. The internal bisectors of B and C meet each other at O. Find the
measure of the three angles of BCO
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Answer:
B =50
C =40
D =90
Step-by-step explanation:
A = 80
C=80 ( opp. angle of parallelogram)
B = 100 (co.interior angle sum)
D=100(opp. angle of parallelogram)
In triangle BCO
angle B=50. (100\2)
angle C =40. (80\2)
angle O =90. (180-50-40)
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