ABCD IS quadrantal in which AB equal to CD and AD equal to BC show that it is a parallelogram in one of the diagonal
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given ,
AB = CD
AD = BC
to prove that : ABCD is a IIgram
proof :- AB = CD (from the given )
BC = AD (from the given )
BD = BD (common side )
∴ Δ ADB ≡ Δ DBC by SSS congruence rule .
therefore from CPCT we can write that ∠ADB
= ∠ DBC (alternate interior angle )
since the alternate interior angles and opposite sides are equal in a quadrilateral therefore it is a IIgram .
i hope it helps ....................^_^
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