ABCD is quadrilateral E,F,G and H are the midpoints of AB,BC,CDandDA respectively .prove that EFGH is a parallelogram.
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GIVEN, quad ABCD
E,F,G,H are mid points
To Prove, EFGH is a parallelogram.
Proof,
Join AC and BD,
In ∆ADC
H is mid point of AD and G is mid point of DC.
So by mid point theorem,
HG || AC and HG= AC/2.......(1)
Similarly,
EF ||AC and EF =AC/2........(2)
By (1) & (2),
HG || EF and HG=AF
We know,
If in a quad opposite sides are equal and parallel then it is a parallelogram.
Hence proved
E,F,G,H are mid points
To Prove, EFGH is a parallelogram.
Proof,
Join AC and BD,
In ∆ADC
H is mid point of AD and G is mid point of DC.
So by mid point theorem,
HG || AC and HG= AC/2.......(1)
Similarly,
EF ||AC and EF =AC/2........(2)
By (1) & (2),
HG || EF and HG=AF
We know,
If in a quad opposite sides are equal and parallel then it is a parallelogram.
Hence proved
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muralikrishna49:
nice answer thxx....
Answered by
65
good morning
very nice question and here is your answer
Given : quad ABCD E,F,G,H are mid points of AB , BC , CD , DA .
To Prove, EFGH is a parallelogram.
Construction : Join daignols AC and BD
In ∆ADC E , H are the midpoints of AD and DC
we know that a line segment joining the mid point of any two sides of a triangle is parallel to the third side and half of it .
HG || AC and HG = AC/2..(1)
Similarly in ΔABC , F AND G are the mid points of AB and BC .
we know that a line segment joining the mid points of any two sides of a triangle is parallel to the third side and half of it .
FE ||AC and FE =AC/2..(2)
From (1) & (2), HG || FE and HG = FE
we know that in any quadrilateral if the opposite sides are equal and parallel it is said to be a parallelogram .
Hence proved that EFGH is a parallelogram
hope this helps you
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