ABCD is quadrilateral E,F,G and Hare the midpoints of AB,BC,CD and DA respectively. prove that EFGH is a parallelogram
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- Draw a quadrilateral ABCD and draw their midpoints E, F, G, H respectively
- join the mid points e ,f ,g ,h
- triangle OHE congruent triangle OFE ( by RHS )
- traingle GOH convruent traidngle GOF (by RHS)
- so, angle HOE + angle FOE + angle FOG + angle HOG = 360 degree
- HF ll AB ll DC ( by mid point theoram )
- hence , EFGH is a parralellogram
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