Question

ABCD is quadrilateral in which ∠A=∠B, ∠D:∠A= 2:1 ∠C=∠B-20. Find the measurer of smaller angle.
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Answer 1

Answer:

acc to ratio angle D /angle A= 2:1

so let ratio be x

therefore D=2x and A=1x

now

also A=B = x

and C= B-20 = x-20

now , using sum of all angles of a quadrilateral

A+B+C+D=360

x+x+(x-20)+2x=360

2x+x-20+2x=360

5x-20=360

5x=360+20

5x=380

x=380/5

x=76

therefore value of x is 76

now A=B=76

C=76-20 = 56

D= 2*76=152

hence solved