Question

ABCD is rectangle BD and AC are diagonal intersect at O angleAOB is y and angleBCO is x and angleOBC is 30degree.Findx+y​

Answer 1

Step-by-step explanation:

In rectangle ABCD,

In rectangle ABCD,BD and AC are diagonal intersect at O.

Angle AOB=y...... (1)

Angle BCO=X.....(2)

Angle OBC=30°...... (3)

x+y=?

In triangle BOC,

Angle BCO=Angle OBC... (OC=OB)

But Angle OBC=30°.... (from 3)

Therefore Angle BCO=x=30°....(4)

In rectangle ABCD,

Angle ABC=Angle ABD+Angle DBC

90°=Angle ABO+Angle OBC

90°=Angle ABO +30° Angle ABO=90°-30°

Angle ABO=60°........(5)

Angle BAO=60°.... (AO=BO)... (6)

Angle AOB=y=60

x+y=30°+60°

x+y=90°