abcd is rectangle in which (ac)=8.4cm.p is the point of intersection of the diagonals.what is (bp)?
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In rect ABCD
AC=BD
P IS A POINT OF INTERSECTION OF DIAGONALS
IN RECTANGLE DIAGONAL BISECT EACH OTHER
DIAGONAL BISECT RECTANGLE AT THERE MIDBOINT
SO,
AC=BD
8.4=2BP
8.4/2=BP
4.2=BP
AC=BD
P IS A POINT OF INTERSECTION OF DIAGONALS
IN RECTANGLE DIAGONAL BISECT EACH OTHER
DIAGONAL BISECT RECTANGLE AT THERE MIDBOINT
SO,
AC=BD
8.4=2BP
8.4/2=BP
4.2=BP
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