Question

ABCD is rectangle whose three vertices are B(4,0), C(4,3) and D(0, 3).
Calculate the length of one of its diagonals.
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Answer 1

AnswEr:-

AB =4 units, BC =3 units

Using Pythagoras theorem,

$\implies AC^2 = AB^2 + BC^2 \\\\ = 4^2 + 3^2 \\ \\ = 16 + 9 = 25 .\\\\\implies \boxed{AC=5 cm}.$

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Answer 2

Answer:- you need to draw it on graph....

first plot it on graph , and then by Pythagoras theorem we will get....

BC:- 3 units

DC:- 4 units

BD:- ? units

by Pythagoras theorem ,

BD²= BC² + DC²

BD = √3² +√4²

BD = √9+16

BD = √25

BD = 5 UNITS

HENCE THE DIAGONAL OF THE RECTANGLE IS 5 UNITS