Question

ABCD is rhombus is which AC=9.6 cm and BD=12.8 cm. find the perimeter of ABCD. ​

Answer 1

Answer:

if AC and BD is the diagonal of Rhombus then

P = 2 squre root ( D1^2 + D2^2)

P = 2 square root ( 9.6^2 + 12.8^2)

P = 2 square root ( 92.16 + 163.84)

P = 2 sqr root (256)

P = 2 × 16

P = 32

answer.

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