ABCD is rhombus whose diagonal intersect at 0.if AB=10 CM, diagonal BD=16 CM, find the length of diagonal AC.
Answers
Answered by
9
Given:-
AB= 10 cm
BD = 16 cm ( diagonals)
AC = ?
BO = OP = 16/2 = 8cm
in question given it is rhombus and it bisect the diagonals at 90 degree
we will use Pythagoras theorem to find AC
AB ² = OA² + OB²
10² = OA² + 8²
100 = OA² +64
100 -64 = OA²
36 = OA²
OA= √36
OA = 6cm
so the length of the diagonal = 6+6 = 12cm
answer = 12cm
Similar questions