ABCD is rhombus with AC =16cm and AB=10cm. find the area of rhombus ABCD
ps:there is no figure in this sum
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Answer:
let ABCD is a rhombus whose diagonals AC and BD meet at point O. Angle B=60°given so that angle ABO =30°. AB=BC=CA=AD=10cm.
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Answer:
Step-by-step explanation:
area for a rhombus is A=(p*q) /2
(10*16)/2 =80
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