Math, asked by aravind1065, 1 year ago

ABCD is Squre Eand F are respectively the midpoints of BC andCD.if R is the midpoint ofEF prove that ar(AER)=ar(AFR)

Answers

Answered by Anonymous
6
Hey mate.....here is ur ans...✌❤❤

In triangle AER and AFR
Since R is the mid point of EF so RE = RF
AR = AR ( commom )
AE = AF ( since joining with their mid points)
so by SSS congruency
AER ~=~ AFR

Now we know that when two triangles are congruent there areas are equal so
ar AER = ar AFR

hope it helps u....thanks....✌❤❤
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Answered by SMALLSMOKE2NO9
0

Step-by-step explanation:

Characteristics of cork are as follow

Cells of cork are dead, compactly arranged and have no intercellular spaces. It forms bark of the tree, which is several layers thick. ... Cork is formed by secondary Lateral Meristem called cork cambium. The mature cork becomes dead and filled with tannin, resin.

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