Question

ABCD is the floor of a box with AB=12cm and BC=16cm. Can a pencil of length 21 cm fit into the Box if kept diagonally on the floor along AC?

Answer 1

Diagonal =  √ 12² + 16²

                   = √400 = 20cm

so 21 cm pencil cant possible .

OK

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THANKS.

Answer 2

${ac }^{2} = {ad}^{2} + {cd}^{2}$

12+16=AC

${12}^{2} + {16}^{2} = {ac}^{2}$

$144 + 256 = {ac}^{2}$

$400 = {20}^{2}$

since the

${ac}^{2} = {20}^{2}$

hence,

21 cm pencil can't be possible