ABCD is the midpoint M of the diagonal BD of the parallelogram; BM is the value of angle AMB if bisects the angle ABC.
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ABCD is a parallelogram in which M is the mid point of diagonal BD , BM bisect
the angle ABC. , therefore angle ABD = angle CBD = x°(let)……………..(1)
AD| | BC and BD is transversal ,
therefore angle ADB = angle CBD. (Alternate angles).
or. Angle ADB = x°…………………………..(2)
From eqn. (1) and (2)
Angle ABD = angle ADB. => side AB = side AD. , ( In ∆ ABD opposite angles are
equal , thus opposite sides are equal.)
∆ ABD is an isosceles triangle in which M is the mid point of base BD ,
angle AMB = angle AMD.
Thus , angle AMB =180°/2 = 90°
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