ABCD is the quadrilateral and the bisector of angle a and b meet AC in O show that AB/BC = AD/CDpls gives the solution
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★ Sᴏʟᴜᴛɪᴏɴ ★
In ∆ABD & ∆CBD
➳ AD = CD [Given]
➳ BD = BD [Common]
➳ AB = BC [Given]
➳ ∆ABD ≅ ∆CBD [SSS]
➳ ∠ABD = ∠1
➳ ∠CBD = ∠1
➳ ∠1 = ∠2 [CPCT]
Also
➳ ∠3 = ∠4 [ CPCT]
⛬ BD bisects both the angles ABC and ADE
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