ABCD IS TRAPEZIUM AB PARALLEL TO DC . AB =10cm AD = BC = 4cm ANGLE DAB = angle CBA = 60º FIND CD AND DISTANCE BETWEEN AB AND CD
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APAD=cos60∘APAD=cos60∘
=> x4=12x4=12
=> x = 2
Therefore, CD = AB - 2x = 10 - 4 = 6 cm
=> x4=12x4=12
=> x = 2
Therefore, CD = AB - 2x = 10 - 4 = 6 cm
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Answer:
Step-by-step explanation:
From △ADP,
APAD=cos60∘
=> x4=12
=> x = 2
Therefore, CD = AB - 2x = 10 - 4 = 6 cm
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