Question

ABCD is trapezium as shown in figure. Distance between two parallel sides AB
and CD is h. DC = 2AB = 2h. Area of ABCD = 384. Find h.

Answer 1

Answer:

384 = (1/2) * (h+h) * 2h

384=(1/2) * 2h * 2h

or, 384*2=$4h^{2}$

or, 192=$h^{2}$

or, h=$8\sqrt{3}$

Step-by-step explanation: