ABCD isa rectangle there is a diagonal AB prove that ange DAC = angle BCA
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Hi there !!
We know that a diagonal divide a rectangle into two congruent triangles of equal areas
To prove : ∠DAC = ∠ BCA
In triangles DAC and BCA ,
DC = BA [common]
∠ADC = ∠CBA [each 90°]
AD = BC
[opp. sides of a rectangle are equal]
Hence ,
ΔDAC ≅ Δ BCA [SAS]
∠DAC= ∠BCA (cpct)
Hence proved ...... !!
We know that a diagonal divide a rectangle into two congruent triangles of equal areas
To prove : ∠DAC = ∠ BCA
In triangles DAC and BCA ,
DC = BA [common]
∠ADC = ∠CBA [each 90°]
AD = BC
[opp. sides of a rectangle are equal]
Hence ,
ΔDAC ≅ Δ BCA [SAS]
∠DAC= ∠BCA (cpct)
Hence proved ...... !!
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