ABCD quadrilateral prove that; AB + BC + CD> AD
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In a quadrilateral ABCD,
Join the diaonal AC such that the quarilateral is divided into two triangles.
Now using triangle inequality we know that,
AB + BC > AC ....(1)
Also, AC + CD > AD ....(2)
Now adding up the two equation, we get
AB + BC + AC + CD > AC + AD
that means, AB + BC + CD > AD
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