ABCD rectangle with AB = 8cm, BC=16cm and AE=4cm. Find the area of triangle BCE? Is area triangleBCE is equal to the sum of triangleBAE and triangleCDE.why?
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Roshan1694:
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Acc to the question, ABCD rectangle with AB=8cm, BC=16 cm and AE=4 cm.
Area of ΔBCE = 1/2 x base x height = 1/2 x 16 x 8 = 64cm².
Area of ΔABE = 1/2 x base x height = 1/2 x 4 x 8 = 16cm²
Area of ΔCDE = 1/2 x base x height = 1/2 x (16-4) x 8 = 48cm²
Sum of area of ΔABE and ΔCDE = 16cm² + 48cm² = 64cm².
Therefore, yes the area of ΔBEC equal to the sum of the area of DBAE and DCDE.
Area of ΔBCE = 1/2 x base x height = 1/2 x 16 x 8 = 64cm².
Area of ΔABE = 1/2 x base x height = 1/2 x 4 x 8 = 16cm²
Area of ΔCDE = 1/2 x base x height = 1/2 x (16-4) x 8 = 48cm²
Sum of area of ΔABE and ΔCDE = 16cm² + 48cm² = 64cm².
Therefore, yes the area of ΔBEC equal to the sum of the area of DBAE and DCDE.
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27
area of triangle bce = 1/2× base × height
that is 1/2×16×8 = 64 square cm
and yes area of triangle BCE is equal to the sum of the area of another two given triangles.
Area of BAE + AREA OF CDE
=1/2×4×8 + 1/2×12×8
=16 + 48
=64 Proved
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17
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