Question

ABCD represents a square of side 6 cm. F is point on DC such that the area of the triangle ADF is one- third of the area of the square. Find the length of FD?? please please show me step by step?? it's urgent please??

Answer 1

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Answer 2

Length of FD is 4 (cm).

Step-by-step explanation:

1. Given data

  ABCD is square.

 So

 AB =BC=CD=DA= 6 (cm)

2. Area of square ABCD $=(side)^{2}=(6)^{2}=36 (cm^{2})$

3. Given that

   $area of \Delta ADF=\frac{area of square ABCD}{3}$

   $\frac{1}{2}\times DA\times FD=\frac{area of square ABCD}{3}$

   $\frac{1}{2}\times DA\times FD=\frac{36}{3}$

  $\frac{1}{2}\times 6\times FD=12$

  So

  FD = 4 (cm)