ABCD trapezium in which AB||CD and AD=BC show that ∆ABC~=∆B
AD
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ar ABC= ar BAC
they are on same base and between same parallel lines
also, AD=BC
So, ∆ABC=~∆BAC
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bc = bd
ab = ab
angle dab = angle cba
by sas postulate
triangle abc is congurent to triangle bad
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