Abcde×4=edcba, then Find A=?,B=?,C=?,D=?,E=?
Answers
ABCDE×4=EDCBA. What are the values of A, B ,C, D and E?
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E×4 will have to end with even digit A . At the same time A**** \cdot 4 should not overflow into six digit number. Obviously A has to be 2 ( a=1 is not possible because it is odd).
∗∗∗∗E⋅4 should end with A which is 2. So E must be 8 or 3 .
2∗∗∗∗⋅4=E∗∗∗∗;E has to be 8 or 9.
To meet the above two conditions, E has to be 8.
2BCD8⋅4=8DCB2
∗∗∗∗8⋅4=32 will have a carry of 3 to tens place and added to 4⋅D,B has to be odd.Also 4⋅B (in thousands place) should not give a carry to ten thousands place B has to be 1 .
Now d⋅4+3=∗1;d should be 2 or 7 but 2 is already assigned to A . hence D=7
21C78⋅4=87C12
It is easy to see that for C∗4+3=∗C,C=9 fits well.
21978⋅4=87912 is the combination.
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