Question

abcde are 5 integer each have unique value and a>b>c>d>e>0 and c=9. so what is the value of a?

Answer 1

Ans =38

Soln-

given that (a+e)/2=7 & c=9

so--- a+e= 14

so passible combinations of a & e is (13,1),(12,2),(11,3).

Now

a>b>c>d>e>0

case-1-

13 > (12/11/10) > 9 > (8/7/6/5/4/3/2)>1>0

so ===> 3*7=21

case 2->

12 > (11/10) > 9 > (8/7/6/5/4/3) > 2 > 0

so ===> 2*6=12

case 3->

11 > 10 > 9 > (8/7/6/5/4) > 3 > 0

so===> 5

than - 21+12+5=38