Question

ABCDE is a cyclic pentagon of which AB=AC and AC is diameterof the circle. If angleAED=118° ,find the measure of angle BAD​

Answer 1

Answer:

∠DAB is 73°

Step-by-step explanation:

Given ABCDE is a cyclic Pentagon. AB=BC and

AC is the diameter of the circle. If ∠AED=118°. we have to find ∠DAB.

∠ADC and ∠ABC are angles subtended in the semicircle ∴ each 90°

Now, AB=BC ⇒ ∠BAC=∠BCA

By angle sum property in ΔABC

∠BAC+∠ABC+∠BCA=180°

⇒ 2∠BAC+90°=180°

⇒∠BAC=45°

AEDC is a cyclic quadrilateral

⇒∠AED+∠ACD=180°

⇒ 118°+∠ACD=180° ⇒ ∠ACD=62°

In ΔADC, by angle sum property

∠DAC+∠ADC+∠ACD=180°

⇒ ∠DAC+62°+90°=180°

⇒ ∠DAC=28°

Hence, ∠DAB=28°+45°=73°

Answer 2

Answer:

73°

Step-by-step explanation:

question wrong...ab=bc othetwise 2 angles of triangle are 90° which is impossible