Question

ABCDE is a five-sided figure in which, BC, CD are respectively equal to AE, DE and
∠ = ∠. Prove that BE = AC​

Answer 1

Step-by-step explanation

MATHS

In given figure ABCD is a quadrilateral; in which AB=AD. The bisector of ∠BAC and ∠CAD intersect the sides BC and CD at the points E and F respectively. Given A quadrilateral ABCD in which AB=AD and the bisectors of ∠BAC and ∠CAD meet the sides BC and CD at E and F respectively.

Thus, in △CBD, E and F divide the sides CB and CD respectively in the same ratio. Therefore, by the converse of Thale's Theorem, we have EF∣∣BD