ABCDE is a pentagon in which AB || DC and angle A = 120°. If angleD: angle E = 3:5 find angle d
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Answer:
Correct option is D)
In a pentagon ABCDE, AB is parallel to DC and ∠A:∠E:∠D=3:4:5
So, ∠B+∠C=180
o
(Sum of interior angles on the same side of transversal are supplementary.)
Let ∠A=3x,∠E=4x,∠D=5x
Sum of all interior angles of pentagon = 180
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(n−2)=180
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(5−2)=540
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Now,
∠B+∠C+∠A+∠E+∠D=540
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=>180
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+3x+4x+5x=540
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=>12x=360
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=>x=30
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∠E=4x=4×30
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=120
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Step-by-step explanation:
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