ABCDE is a pentagon with center of its circumcircle at point O such that AB =BC=CD and angle ABC 120. Calculate angle BED and angle BED.
Answers
Answered by
3
the angle BED = 60
Mark it as brainlist and press red button
Mark it as brainlist and press red button
Sweatasaha21:
why don't you please explain the answer friend
explain please
how you got it.
Traingle EOD,DOC and COB are equilateral traingle as OE = OD = OC = OB all are radii of the circle and ED = DC = CB so all the 3 sides of all the 3 triangles are equal so by SSS Test All the 3 triangles are congruent
So,
∠EOD = ∠DOC = ∠COB [By C.P.C.T.C]
∠EOD + ∠DOC + ∠COB = 180° [EOB is a straight line]
∠EOD + ∠EOD + ∠EOD = 180°
3∠EOD = 180
∠EOD = 60 = ∠COD = ∠BOD
Therefore,
∠COD = ∠BOD = 60°
BOD = BED = 60 (angle in same segment)
So,
∠EOD = ∠DOC = ∠COB [By C.P.C.T.C]
∠EOD + ∠DOC + ∠COB = 180° [EOB is a straight line]
∠EOD + ∠EOD + ∠EOD = 180°
3∠EOD = 180
∠EOD = 60 = ∠COD = ∠BOD
Therefore,
∠COD = ∠BOD = 60°
BOD = BED = 60 (angle in same segment)
add it as brainlist
Sides AB=BC=CD, not DE
ok
thanks I solve this problem using your concept.
Similar questions