ABCDE is a regular pentagon and bisector of
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ABC
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Actually,Bisector formula is n×(n-3)÷2
where n is number of sides
So,Pentagon has five sides
5×(5-3)÷2=5×(2)÷2=5
So,the number of Diagonals in an pentagon are 5
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where n is number of sides
So,Pentagon has five sides
5×(5-3)÷2=5×(2)÷2=5
So,the number of Diagonals in an pentagon are 5
Was my answer helpful to you?Comment please.
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