Question

ABCDE is a regular pentagon and bisector of ∠BAE meets CD at M. if bisector of ∠BCD meet AM at P, find ∠CPM.

Please answer it's an emergency...

Answer 1

Answer: heyyy~

∠CPM= 36°

Step-by-step explanation:

the total angle of pentagon = 540°

each angle = 108°

in quadrilateral ABCP,

angle PAB = 54°

angle ABC = 108°

angle BCP = 54°

angle CPA = x°

angle PAB +angle ABC +angle BCP +angle CPA = 360° (angle sum property of quadrilateral)

54° + 108° + 54° + x° = 360°

x° = 144°

angle CPM = 180° - x° (linear pair)

angle CPM = 36°

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