ABCDE is a regular pentagon if angle abc is equal to 36 degree find angle 1 2 3
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Step-by-step explanation:
we know that sum of angles A , B,C,D and E = 540 degree
there fore each angle A , B,C ,D and E measures = 108 degree
Angle A = 108 degree
now in triangle ABE ,
AB=AE ( because it is regular pentagon, all sides are equal)
so Triangle ABE is isosceles triangle.
Angle ABE = angle AEB (i)
now angle A + angle AEB+ angle AEB = 180
104 + 2 angle ABE= 180 (because of (i) )
angle AEB =36 degree (which is angle 2)
similarly angle 3 = 36 degree
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