ABCDE is a regular pentagon prove that angle BAC is equal to angle c a d is equal to angle EAD is equal to angle ACE
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Sum of the interior angles of the pentagon ABCDE = 180 ° n - 2 , where n is the number of sides = 180 ° 5 - 2 = 180 ° 3 = 540 ° Since , ABCDE is a regular pentagon. ⇒ Each interior angle = 540 ° 5 = 108 ° Now draw two diagonals joining BE and BD . We need to find the angles of the ∆ BDE .
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