ABCDE is a regular pentagon.The bisector of meets CD at M. Find
Answers
Answered by
1
Answer:
we know that sum of interior and exterior of a pentagon is 540° [(n-2)×180] and each angle = 108° .
therefore ..bisector angle a =54°
now in quadrilateral abcm,
a+b+c+m=180°
therefore
54+108+108+amc=360
270+amc=360
amc= 360-270=90
hence proved!.
Pls mark branliest
Answered by
0
Answer:
54 DEGREE
Step-by-step explanation:
Similar questions