Question

ABCDE is a regular polygon AF bisects Angle BAE and meets CD at point F.find angle AFD

Answer 1

Answer:

Each interior angle of a regular pentagon =n2n−4×90

=52×5−4×900

=6×18=1080

∴∠BAM=21(1080)=540

In the quadrilateral ABCM,

∠BAM+∠ABC+∠BCM+∠AMC=3600

⇒540+1080+1080+∠AMC=3600

⇒∠AMC=900

Step-by-step explanation:

Answer is 90°