Question

ABCDE is
regulao Pentagor find the
measure of Angle DAC and Angle ADE​

Answer 1

Answer:

The sum of angle of pentagon =540  

0

 

Then one angle of pentagon is 108  

0

 

In ΔADE , angle ADE=angle EAD (b) because (AE=ED) Side of pentagon

So ∠AED+∠EDA+∠DAE

Or 108+b+b=180 or 2b=180-108=72  

0

 

Or b=36  

0

 

In triangle ADC , side AD=AC diagonal of pentagon  

Then ∠ADc=∠ACD=a

And ∠ADC=∠EDC-∠EDA

Then ∠ADC=108-36=72  

0

 

But ∠ACD(c)=∠ADC=72  

0

 

In triangle ADC

∠DAC(a)=180-∠DCA-∠ADC

So ∠DAC(a)=108-72+72=36  

0

 

Then a=36  

0

 ,b=36  

0

 and c=72  

0

 

Step-by-step explanation:

Answer 2

Answer:

yes/no

Step-by-step explanation:

???????????????????