Math, asked by youshenee3267, 2 months ago

abcdef is a regular hexagon.
a) what is the the measure of each angle in a regular hexagon ?
b) what type of triangle is bcd?
c) find all angles of bcd
d) what type of triangle of bde?
e) find all angles of bde.
f) find all angles of the quadilateral abef.

Answers

Answered by shaziafaisalshamsi14
0

1. A hexagon has six sides, and we can use the formula degrees = (# of sides – 2) * 180. Then degrees = (6 – 2) * 180 = 720 degrees. Each angle is 720/6 = 120 degrees.

2. triangle BCD are isosceles triangle .

3. The formula works like this: c2 = b2 + d2 - 2bd * cos(C). The lowercase letters refer to the side lengths opposite the angles: d is the side opposite angle D, or BC, b is the site opposite angle B, or CD, etc. Substituting in the numbers, we get: 632 = 492 + 762 - 2(49)(76)cos(C).

4. equalateral triangle.

5. Quadrilateral ABEF contains half the angle measure of hexagon; its interior angle measure 360°. ⇒ ∠ ABE = 60°; ∠ EAB = 90° and ∠ AEB = 30° .

its the answer....

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