Question

ABCDEF is a regular hexagon.prove that BD is per pendicular to FC

Answer 1

Step-by-step explanation:

In the last step of the above image, we have obtained that

∆DOC and ∆BOC are congruent,

Hence, we can say

angle DOC = angle BOC [Since they are corresponding parts of congruent triangles]

angle DOC and angle BOC are also linear pairs, so,

angle DOC + angle BOC = 180°

=> 2 x angle DOC = 180°

=> angle DOC = 180°/2

=> angle DOC = angle BOC = 90°

Hence proved that, BD is perpendicular to FC.