ABCDis a rectangle and x and y are points on sides AD and B.C such that AY=BX.
SHOW THAT <ABX=<BAY
no spamsss
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in triangleABX AND ABY
AB=AB COMMAN SIDE
<XAB=<YBA EACH 90°
BX=AY GIVEN
tri
CrimsonHeat:
how XAB is 90
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given:ABCD is a rectangle x and y are the point on AD and BC such that AY=BX
To prove :<ABX=<BAY
PROOF:in triangle ABX and triangle BAY
AB=BA (common)
AY=BX (given )
<BAY=<ABY (each of 90°)
so,triangle ABX congruent to triangle BAY (by SAS criteria )
so, <ABX=<BAY (C.P.C.T)
Hence proved.
hope it helps you. ......
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