Question

ABCis triangle right angeld at c. a line through the midpoint m of hypotenuse AB and parallel to BC intersect AC at D show that. for​

Answer 1

Step-by-step explanation:

R.E.F. Image.

In △ABC,

(1) M is the mid point of AB and

MD∥BC

D is the mid point of AC

(2) As MD∥BC &

AC is transversal

∠MDC+∠BCD=180

∘

∠MDC+90

∘

=180

∘

⇒∠MDC=90

∘

⇒MD⊥AC

(3) In △AMD and △CMD

AD=CD

∠ADM=∠CDM

DM=DM

△AMD≅△CMD

AM=CM⇒AM=

2

1

AB⇒CM=AM=

2

1

AB

Answer 2

Answer:

Given :- m is the mid point of AB and mD parallel to BC.

To Prove :- D is the mid point of AC.

Step-by-step explanation:

If m is the mid point of Ab, then D is the mid point of AC (because of converse of mid point theorem).

Hope the answer helps. ❤