Question

ABD =66° and ACD=60° if bisector of A meets BC at D find ADB​

Answer 1

Answer:87

Step-by-step explanation:

angle (a+b+c )=180°.66°+60°+a= 180°.a=180°-126°》54°.in triangle ABD ,angle ADB=180°-(66°+54°/2)=180°-93°=87°.

Answer 2

Answer:

Step-by-step explanation:

It's very easy.

See, first of all in triangle ABC, we apply angle sum property;

<A+<B+<C=180°

<A+66°+60°=180°

<A+126°= 180°

<A= 54°

Then, AD is the bisector of <A.

Therefore, <BAD=<CAD=54/2= 27°.

Then, we will apply angle sum property in triangle BAD.

<BAD+<B+<ADB=180°

27° + 66° +<ADB = 180°

93° + <ADB = 180°

<ADB=180°-93°

<ADB= 87°. Ans